Which of the following half-reactions would occur at the anode of an electrochemical cell?
A. H+(aq) + Cl− (aq) → HCl(aq)
B. Cu(s) → Cu+(aq) + e−
C. Cu+(aq) + e− → Cu(s)
D. Li+(aq) + e− → Li(s)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (vera_ewing):
@aaronq
OpenStudy (vera_ewing):
@Jesstho.-. help!!!
OpenStudy (aaronq):
so (from the previous question) what happens at the anode?
OpenStudy (vera_ewing):
oxidation
OpenStudy (aaronq):
right, so which one of these equations is an oxidation reaction?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (vera_ewing):
B?
OpenStudy (anonymous):
Exactly.
The half-reaction on the anode, where oxidation occurs, is Zn(s) = Zn2+(aq) + 2e-. The zinc loses two electrons to form Zn2+. The half-reaction on the cathode where reduction occurs is Cu2+(aq) + 2e- = Cu(s).
OpenStudy (aaronq):
yup!
OpenStudy (vera_ewing):
so the answer is B?
OpenStudy (anonymous):
The entire reaction can be written by combining both half-reactions: Zn(s) + Cu2+(aq) = Zn2+(aq) + Cu(s)
Still Need Help?
Join the QuestionCove community and study together with friends!