Question

More end behavior help please? Check my answer?

Answer 1

Leaning toward C or D

Answer 2

@Catch.me

Answer 3

Can you do the same steps which I did?

Answer 4

There is a quick way to solve infinity problems:
just take the greatest power of x and take its coefficient then multiply it by infinity to the greatest x power. That should solve it by just looking at the equation.

Answer 5

when you expand (or by inspection) the highest power is x^3 the coefficient is -2
when x is positive then -2x^3 is negative
when x is negative then (-x)^3 is negative and then *-2 gives a positive so y is positive

Answer 6

x approaches negative infinity y is positive and x approaches infinity y is negative
y = f(x)

Answer 7

Can you Decide now?

Answer 8

Hint:
please note that I can re-write your function as below:
\[f(x)=x ^{3}\left( 2+\frac{ 1 }{ x } \right)\left( 1+\frac{ 2 }{ x } \right)\]

Answer 9

Here's (another) easy way to do it:

Treat it the same way you'd treat regular multiplication -

(negative)*(negative)=positive
(positive)*(negative)=negative
(positive)*(positive)=positive

Answer 10

here is another way
the degree is 3
3 is odd
the leading coefficient is negative
those two facts should be good enough

Answer 11

@satellite73 so its C?

Answer 12

So take for instance plugging in +infinity. Treat it as plugging in (positive).

-(positive)*(positive*positive+positive)*(*positive*positive+positive)

OR simplified:

(negative)*(positive)*(positive)<=>(negative)*(positive)<=>negative

So when plugging +infinity as x you get -infinity in f(x).

Answer 13

Lol.

Answer 14

No it is not C