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Mathematics 14 Online
OpenStudy (anonymous):

How can I solve these problems?

OpenStudy (anonymous):

OpenStudy (freckles):

what is that p word ? sequence to see what ..... generated? ... anyways I also see it says find some terms let's find the first 5 terms for a and see what they look like first term is given a_1=2 to find the second term enter in 1 for n this will give you on the left hand side a_2 try it

OpenStudy (anonymous):

pattern..

OpenStudy (anonymous):

can u give me an example? I don't know what you are talking about. sorry

OpenStudy (freckles):

You don't see n?

OpenStudy (freckles):

\[a_1=2 \\ a_{n+1}=a_n+2 \] You see those n's ?

OpenStudy (freckles):

in the subscript area?

OpenStudy (freckles):

replace them with 1

OpenStudy (freckles):

\[a_{1+1}=a_1+2 \]

OpenStudy (freckles):

now that first subscript can be simplified to 2 so you have \[a_2=a_1+2\]

OpenStudy (freckles):

but a_1 is 2 so you know \[a_2=2+2\]

OpenStudy (freckles):

so a_2 is 4 that is the second term of the sequence is 4

OpenStudy (freckles):

try finding a_3 now

OpenStudy (freckles):

replace the n's with 2 instead of 1

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

is it 10?

OpenStudy (freckles):

\[a_{n+1}=a_n+2 \\ \text{ replace } n \text{ with 2 } \\ a_{2+1}=a_2+2 \\ a_3=a_2+2 \\ \text{ we just found } a_2 \text{ to be 4 }\]

OpenStudy (anonymous):

6?

OpenStudy (freckles):

yes 4+2 is 6

OpenStudy (freckles):

not 10

OpenStudy (freckles):

so far we have 2,4,6 are the first three terms of the sequence in order

OpenStudy (freckles):

you can find the 4th term if the you aren't sure what pattern is here so far

OpenStudy (anonymous):

why did u add the 4 with 2? even though, the problem said to add with 5?

OpenStudy (freckles):

because it says to add 2

OpenStudy (freckles):

\[a_{n+1}=a_n+2 ; a_1=2 \\ \text{ replace } n \text{ with 1 } \\ a_{1+1}=a_1+2 \\ a_2=a_1+2 \\ \text{ we are given } a_1 \text{ is } 2 \\ a_2=2+2=4 \\ \text{ now replace the } n's \text{ with 2 } a_{2+1}=a_2+2 \\a_3=a_2+2=4+2=6\]

OpenStudy (anonymous):

I thought u were doing problem b. nevermine

OpenStudy (anonymous):

thanks

OpenStudy (freckles):

oh no I have been working with a from the very go

OpenStudy (anonymous):

okay, yea that's why I was confused.

OpenStudy (freckles):

that is why i kept adding 2 and not 5

OpenStudy (anonymous):

yea, I understand now

OpenStudy (anonymous):

Can you help with question 5 also?

OpenStudy (freckles):

have you done number 4 yet I think that might be important for 5 because I think the difference equations they are talking about are the one's in 4 could be wrong about that

OpenStudy (freckles):

you can find the first few terms and should be able to match it to a sequence in 4

OpenStudy (anonymous):

still doing number 4

OpenStudy (freckles):

for example 4a is 2,4,6,8,10,... and so on... 5d is also 2,4,6,8.10,... I know this from finding the first few terms \[a_n=2n \\ a_1=2(1)=2 \\ a_2=2(2)=4 \\ a_3=2(3)=6 \\ a_4=2(4)=8\] and so on...

OpenStudy (freckles):

we clearly see that 5d is equivalent to 4a

OpenStudy (anonymous):

ahh i think i will have to match the equations from question 4 to the equations in question 5 right?

OpenStudy (freckles):

that is what I'm thinking

OpenStudy (anonymous):

I am having a problem with question 4, e. Can you explain how to do that to me.

OpenStudy (freckles):

you could do 4d though ?

OpenStudy (freckles):

e and d are very similar

OpenStudy (anonymous):

mhm I guess I don't know how to do d either then. I thought it was just adding 1 everytimes for the d.

OpenStudy (freckles):

oh no

OpenStudy (freckles):

let's look at 4d then

OpenStudy (freckles):

\[a_{n+1}=-a_n ; a_0 =1 \] this is what is given

OpenStudy (freckles):

so they are using a_0 as first term instead of a_1

OpenStudy (freckles):

so we need to find the second term a_1 to do this we need to replace n with 0

OpenStudy (freckles):

\[a_{0+1}=-a_{0} \\ a_1=-a_0\]

OpenStudy (freckles):

we are given a_0 is 1 right

OpenStudy (freckles):

we are given a_0 is 1 right\[a_1=-(1) \\ a_1=-1 \]

OpenStudy (freckles):

it is multiplication not addition

OpenStudy (freckles):

\[a_{n+1}=-a_n \text{ can be read like this } \\ a_{n+1} =(-1)a_n\]

OpenStudy (freckles):

\[\text{ or like this } a_{n+1} =-1 \cdot a_n\]

OpenStudy (freckles):

first term is 1 second term is -1(1)=-1 third term is -1(-1)=1 we are just taking the previous term and multiplying it be -1 to get the term after

OpenStudy (anonymous):

Okie, I did all the steps correct then, just got the pattern wrong.

OpenStudy (anonymous):

for it would it be like this ----- a1 + 1 = 2a1 --- a2 = 4?

OpenStudy (anonymous):

e*

OpenStudy (freckles):

I'm not totally sure what all that is before the a2=4 thing but if you are saying a2 is 4 then you are right because 2(2)=4

OpenStudy (freckles):

so just like before to get the term in question we are taking the previous term and multiplying it by 2 (instead of -1)

OpenStudy (anonymous):

yea that's what I did :D. Thank you so much. U helped me alot!

OpenStudy (freckles):

cool stuff it should be kinda obvious which choice from 4 should match up with what choice from 5 since I told you 4a=5d I say this because 4b and 4c are similar to 4a

OpenStudy (freckles):

so do you think you can match them all up even without finding the first few terms?

OpenStudy (anonymous):

yes, i finished it already

OpenStudy (freckles):

nice work

OpenStudy (anonymous):

thanks. u too

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