How can I solve these problems?
what is that p word ? sequence to see what ..... generated? ... anyways I also see it says find some terms let's find the first 5 terms for a and see what they look like first term is given a_1=2 to find the second term enter in 1 for n this will give you on the left hand side a_2 try it
pattern..
can u give me an example? I don't know what you are talking about. sorry
You don't see n?
\[a_1=2 \\ a_{n+1}=a_n+2 \] You see those n's ?
in the subscript area?
replace them with 1
\[a_{1+1}=a_1+2 \]
now that first subscript can be simplified to 2 so you have \[a_2=a_1+2\]
but a_1 is 2 so you know \[a_2=2+2\]
so a_2 is 4 that is the second term of the sequence is 4
try finding a_3 now
replace the n's with 2 instead of 1
ok
is it 10?
\[a_{n+1}=a_n+2 \\ \text{ replace } n \text{ with 2 } \\ a_{2+1}=a_2+2 \\ a_3=a_2+2 \\ \text{ we just found } a_2 \text{ to be 4 }\]
6?
yes 4+2 is 6
not 10
so far we have 2,4,6 are the first three terms of the sequence in order
you can find the 4th term if the you aren't sure what pattern is here so far
why did u add the 4 with 2? even though, the problem said to add with 5?
because it says to add 2
\[a_{n+1}=a_n+2 ; a_1=2 \\ \text{ replace } n \text{ with 1 } \\ a_{1+1}=a_1+2 \\ a_2=a_1+2 \\ \text{ we are given } a_1 \text{ is } 2 \\ a_2=2+2=4 \\ \text{ now replace the } n's \text{ with 2 } a_{2+1}=a_2+2 \\a_3=a_2+2=4+2=6\]
I thought u were doing problem b. nevermine
thanks
oh no I have been working with a from the very go
okay, yea that's why I was confused.
that is why i kept adding 2 and not 5
yea, I understand now
Can you help with question 5 also?
have you done number 4 yet I think that might be important for 5 because I think the difference equations they are talking about are the one's in 4 could be wrong about that
you can find the first few terms and should be able to match it to a sequence in 4
still doing number 4
for example 4a is 2,4,6,8,10,... and so on... 5d is also 2,4,6,8.10,... I know this from finding the first few terms \[a_n=2n \\ a_1=2(1)=2 \\ a_2=2(2)=4 \\ a_3=2(3)=6 \\ a_4=2(4)=8\] and so on...
we clearly see that 5d is equivalent to 4a
ahh i think i will have to match the equations from question 4 to the equations in question 5 right?
that is what I'm thinking
I am having a problem with question 4, e. Can you explain how to do that to me.
you could do 4d though ?
e and d are very similar
mhm I guess I don't know how to do d either then. I thought it was just adding 1 everytimes for the d.
oh no
let's look at 4d then
\[a_{n+1}=-a_n ; a_0 =1 \] this is what is given
so they are using a_0 as first term instead of a_1
so we need to find the second term a_1 to do this we need to replace n with 0
\[a_{0+1}=-a_{0} \\ a_1=-a_0\]
we are given a_0 is 1 right
we are given a_0 is 1 right\[a_1=-(1) \\ a_1=-1 \]
it is multiplication not addition
\[a_{n+1}=-a_n \text{ can be read like this } \\ a_{n+1} =(-1)a_n\]
\[\text{ or like this } a_{n+1} =-1 \cdot a_n\]
first term is 1 second term is -1(1)=-1 third term is -1(-1)=1 we are just taking the previous term and multiplying it be -1 to get the term after
Okie, I did all the steps correct then, just got the pattern wrong.
for it would it be like this ----- a1 + 1 = 2a1 --- a2 = 4?
e*
I'm not totally sure what all that is before the a2=4 thing but if you are saying a2 is 4 then you are right because 2(2)=4
so just like before to get the term in question we are taking the previous term and multiplying it by 2 (instead of -1)
yea that's what I did :D. Thank you so much. U helped me alot!
cool stuff it should be kinda obvious which choice from 4 should match up with what choice from 5 since I told you 4a=5d I say this because 4b and 4c are similar to 4a
so do you think you can match them all up even without finding the first few terms?
yes, i finished it already
nice work
thanks. u too
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