Question

A bag contains several marbles. Some are red some are white and some are blue. The probability of drawing a red marble is 1/6 and the probability of drawing a white marble is 1/3 .
What is the probab of drawing a blue marble?
What is the smallest number of marbles that could be in the bag?
Could the bag contain 48 colors? If so how many of each color?
If the bag contains four red marbles and eight white marbles how many blue marbles?

Answer 1

For the first one I was thinking 3/6 but then I don't know and im not so sure

Answer 2

1-(1/6+1/3)

Answer 3

Only red, white, and blue marbles are in the sack.

Prob of red, white, or blue = 1.

1 - 1/6 - 1/3 = 3/6 or 1/2 for the prob of blue.

Answer 4

The plot thickens:

What is the smallest number of marbles that could be in the bag?

Answer 5

Ooh I see I just did it by doing this 1/6 + 1/3 = 3/6=1/2

Answer 6

6?

Answer 7

I'm looking at the denominators of the fractional probabilities and thinking maybe the answer is the LCM of 6, 3, and 6.

Least Common Multiple is 2 * 3 = 6

Answer 8

I think we should check that against the original info to see if it works.

Answer 9

Well, that is so obvious that I didn't see it. Six, yes.

Answer 10

What about this:

Could the bag contain 48 colors? If so how many of each color?

Answer 11

Lol and yes I thinks its correct cause 1/6 + 1/3+ 1/2= 6/6 =1

Answer 12

I can buy into that.

Answer 13

I meant 48 marbles not colors

Answer 14

I'm thinking about dividing 6 into 48 and then doing something. Just an idea.

Answer 15

24/48 and umm

Answer 16

Do the other two colors.

Answer 17

>>24/48 That is only the blues, right?

Answer 18

No 8/48 reds and 16/48 whites

Answer 19

Wait yess I guess since they add up to 24/48and thats half of 48 then theres 24/48 blue ones

Answer 20

There are two questions here:

Could the bag contain 48 colors?

If so how many of each color?

Answer 21

I mean could the bag contain 48 marbles not colors sorry about that

Answer 22

How do you answer this one: Could the bag contain 48 marbles?

Answer 23

So yes and 8/48 red 16/48 white and 24/48 blues which simplify to 1/6 1/3 and 1/2

Answer 24

Yes.

8 red, 16 white, and 24 blue


I agree.

Answer 25

Now this:

If the bag contains four red marbles and eight white marbles how many blue marbles?

Answer 26

I put 3/4 cause I dont know their denominator so I just did this 4/48 + 8/48= 12/48 1/4 so for blue ones is 3/4 which in total 1/4+3/4 =4/4=1 ?

Answer 27

Oh I just noticed that the answers we gor from before are being umm idk how to explain it watch
8/48 16/48 24/48
4/48 8/48 12/48

Answer 28

P(R) = 1/6
P(W) = 2/6
P(B) = 3/6

4 reds 4/? = 1/6

8 whites 8/? = 2/6

Here's where I am so far.

Answer 29

How ? Did you get 8?

Answer 30

x = 24

4/24 + 8/24 + x/24 = 1

x will be the blues

Answer 31

12/24 = 3/6

Answer 32

So, 12 blues.

Answer 33

>> How ? Did you get 8? I'm not sure which 8 you mean.

Answer 34

Okay yes I understand . Oh 8 whites 8/? But I guess you divided 2 to 18/48

Answer 35

P(R) = 1/6 = 4/24

P(W) = 2/6 = 8/24 -this 8 comes from writing 2/6 as a fraction with a denominator of 24

P(B) = 3/6 = 12/24

Answer 36

YeH yeah I see now from observing what you did. Thank you so much

Answer 37

You are welcome. It turned out to be a problem in writing fractions in equivalent forms with different denominators.

Answer 38

Because we are preserving the original probability fractions while writing them with the same different from original denominator.