Question

Need help setting this up. H(x) = sqr root (x+6). Find the function h(7t-7), t > or = 1/7

Answer 1

\[h(x)=\sqrt{x+6}\]
\[h(7t-7)=\sqrt{7t-7+6}=\sqrt{7t-1}\]

Answer 2

Ok so was the t greater than or equal to 1/7 sort of unnecessary info?

Answer 3

\[if~7t-1<0,7t <1,t <\frac{ 1 }{ 7 }\]
then we get negative value under the square root
so h(7t-1) is imaginary.
hence 7t-1 should be >= 0

Answer 4

so the information given is not unnecessary.