Question

If a child's knowledge of the alphabet is limited to the letters a, b, c, i, and e, and if the child writes two letters at random (assume the child may write the same letter twice), what is the probability that one is a vowel and the other is a consonant?



6/25

12/25

4/5

Answer 1

@ganeshie8

Answer 2

4/5?

Answer 3

how ?

Answer 4

well cause theres 5 letters

Answer 5

wait its actaully 12/25

Answer 6

simply find the probabilities of each event and multiply

Answer 7

what is the probability that `one is a vowel` and the `other is a consonant`?

Answer 8

how many vowels are there in the given set of letters ?

Answer 9

3/2

Answer 10

got it thnx

Answer 11

you seem to be in rush lol

Answer 12

i am, got a lot to do till tomorrow

Answer 13

i wish you all the best, this is an easy question :
there are 3 vowels in a total of 5 letters so probability for vowel would be 3/5
similarly probabiltiy of consonant would be 2/5

multiplying them gives you the desired probability of having a vowel and consonant : (3/5)*(2/5) = 6/25

Answer 14

it isn't 6/25

Answer 15

the grader marked it wrong is it ?

Answer 16

yep

Answer 17

Oh right, silly mistake! we can have the first letter as "consonant" so the probability would be

\[(3/5)*(2/5) + (2/5)*(3/5) = 12/25\]

Answer 18

oh ok thnx

Answer 19

yw!

Answer 20

if you don't like that you could have also wrote it all out: