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Mathematics 21 Online
OpenStudy (anonymous):

PLEASE HELP WILL GIVE A MEDAL The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the derivative.

OpenStudy (anonymous):

@DanJS

OpenStudy (danjs):

The position s(t) is linear, the velocity will be constant , the same at any time t.

OpenStudy (anonymous):

so how do i find the solution?

OpenStudy (danjs):

The derivative , is the slope of the tangent line at a point on the graph. If the graph is a straight line. The tangent at any point will be the slope of the line. Also, taking the derivative, s ' (t) = v(t) = -6

OpenStudy (anonymous):

okay but then wouldnt it be -6 at t=2

OpenStudy (danjs):

yes, it would be -6 at any time t

OpenStudy (anonymous):

so that would be my answer for the velocity?

OpenStudy (danjs):

it is a straight line for position vs time. The velocity is the change in position vs time, it is always constant , the slope of the line, -6

OpenStudy (anonymous):

oh wow okay thank you!

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