Question

ode refresher and yes I know it's a separable one!
dy/dx=y-y^2

Answer 1

\[\frac{dy}{dx}=y-y^2\]

Answer 2

\[dy \frac{1}{y-y^2}=dx\]

Answer 3

I know the right hand side is x + C by default. but wtheck is going with the left...

Answer 4

I don't think I can split the fraction... so I tried u subsitution which is u = y-y^2 du = 1-2y

Answer 5

but then I get something screwed up and aarrrrghhhh wtheck.

Answer 6

\[\int\limits_{}^{}\frac{1}{y(1-y)} dy=\int\limits_{}^{}1 dx\]
use partial fractions for left hand side

Answer 7

right hand side is pretty easy

Answer 8

oh of course x.x that's the A/wfsdjfsdkl B/ sfjdslkfjdskl such and such

Answer 9

\[\frac{1}{y(1-y)}=\frac{A}{y}+\frac{B}{1-y} \text{ yeah }\]

Answer 10

A/y + B/1-y stuff right? since it's factorable in the denominator... yeah now I remember you're a godsend thank you :)

Answer 11

and then solve for A and B and such and such ok...