Question

Is this correct?

Answer 1

Describe how to transform the graph of f into graph of g
f(x)=\[\sqrt{x}\] g(x)=\[\sqrt{0.5}\] and i think its vertically strech the graph of f by a factor of 50

Answer 2

i think there is a typo

Answer 3

where?

Answer 4

its f(x)=\[\sqrt{x} \] g(x)=\[\sqrt{0.5x}\]

Answer 5

\(\large\color{slate}{ f(x)=\sqrt{x} }\)
\(\large\color{slate}{ g(x)=\sqrt{0.5x} }\)

let's re-write the g(x),

\(\large\color{slate}{ f(x)=\sqrt{x} }\)
\(\large\color{slate}{ g(x)=(\sqrt{~0.5}) \cdot \sqrt{x} }\)

Answer 6

By how much are you stretching the f(x), by what scale factor?

Answer 7

by 2?

Answer 8

(stretch, can be also shrink)

Answer 9

See how I have these to function,

\(\large\color{slate}{ f(x)=\sqrt{x} }\)
\(\large\color{slate}{ g(x)=(\sqrt{~0.5}) \cdot \sqrt{x} }\)
? ?

Answer 10

\(\large\color{slate}{ f(x)=\sqrt{x} }\)
\(\large\color{slate}{ g(x)=(\sqrt{~0.5}) \cdot \sqrt{x} }\)

you are multiplying the g(x) times \(\large\color{slate}{ \sqrt{~0.5} }\)

Answer 11

oh okay

Answer 12

so what are you doing to f(x) to make it g(x) ?

Answer 13

I think f(x) would have to horziontally shrink by a factor of 50?

Answer 14

why 50 ?

Answer 15

oh i calculated wrong. That's what i got in my first answer but i think i did it wrong. It would be by a factor of two since its mutplying (square root of 0.5 ) (square root x) since 0.5 is a factor of two. Wouldnt it just be vertically streched by a factor of 2?

Answer 16

\(\large\color{slate}{ g(x)=(\sqrt{~0.5}) \cdot \sqrt{x} }\)
lets play with g(x),
\(\large\color{slate}{ g(x)=(\sqrt{1/2}) \cdot \sqrt{x} }\)

\(\large\color{slate}{ g(x)=(\sqrt{1}/\sqrt{2}) \cdot \sqrt{x} }\)

\(\large\color{slate}{ g(x)=(1/\sqrt{2}) \cdot \sqrt{x} }\)

(multiplying top and bottom of this fraction time square root of 2,
\(\large\color{slate}{ g(x)=(\sqrt{2}/2) \cdot \sqrt{x} }\)

Answer 17

so its being shrinked?

Answer 18

stretched by sqrt{2}/2, ( yes shrinked.... )

Answer 19

in my answers it says either horizontally or vertically. It's being stretched horizontally right?

Answer 20

Yes.