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simlify 6√64c^12
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*simplify
\[\huge\ 6\sqrt{64c^{12}}\] right ?
or is that 6th root ??
6th root
\[\huge\sqrt[6]{64c^{12}}\] :)
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You can also write it as \[\left( 64c ^{12} \right)^{\frac{ 1 }{ 6 }}\]
so you can change root to exponent for example square root of x can be writtten as one half power \[\huge \sqrt{x} = x^{\frac{ 1 }{ 2 }}\]
ok
\[\huge(64c^{12})^{\frac{ 1 }{ 6 }}\] mean 64 and c^12 both have 1/6 exponent so you can write it as\[\huge (64)^{\frac{ 1 }{ 6 }} \times (c^{12})^{\frac{ 1 }{ 6 }} \] nw solve this
64c 1/3?
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@Nnesha
what is \[\huge\ (64)^{\frac{ 1 }{ 6 }} = ???\]
|dw:1421640412313:dw| for variable you have to multiply inside exponent by out side exponent
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