Question

Solve the equation in the interval [0,2pi].
2sin(t)cos(t)-cos(t)+2sin(t)-1=0. I already factored it and my answers were pi/2, 2pi/3, 4pi/3 but I got it wrong.

Answer 1

you factored by grouping , correct?

Answer 2

Yass

Answer 3

cos(t)[2 sin(t)-1]+1[2 sin(t)-1]=0
[2 sin(t)-1](cos(t)+1]=0

Answer 4

then you set two two factors equal to zero?

Answer 5

are these the equations you got
2sin(t)-1=0
cos(t)+1=0
?

Answer 6

No I got cos(t)=0
and sin(t)-1=0

Answer 7

do you see how I got my equations?

Answer 8

yeah i did thank you so much cx

Answer 9

drew it just in case it made it more prettier to you