A rectangular block of plastic, measuring 1.96 cm by 1.66 cm by 1.94 cm, floats in the middle of the Pacific Ocean. The volume of sea water displaced by the plastic block is 3.77 cm3. Assuming the density of the sea water is 1.025 g/mL, what is the density of the plastic?

Question

danjs · Answer

Density = mass / Volume

Volume block = length x width x height

mass of block = mass of water displaced

danjs · Answer

Mass of displaced Water = Density Of water x Volume Water

danjs · Answer

Start by calculating, mass of the displaced water...

anonymous · Answer

volume of the block is 6.31 cm^3

danjs · Answer

right,
Mass of block = mass of water displaced = Density Water x Volume Water

$$\frac{ 1.025 ~g~water }{ 1~mL~water }*\frac{ 3.77 ~cm^3~water }{ 1 }*\frac{ 1~mL~water }{ 1~cm^3~water } = (1.025)*(3.77) ~g ~water$$

danjs · Answer

Density of Plastic = Mass Plastic / Volume Plastic = 

      [(1.025*3.77) / (6.31)]   g/cm^3