Question

Given the equation 5x + y = 7, which equation below would cause a consistent-independent system?

10x + 2y = 14
-15x - 3y = -6
5x + y = -7
6x + 2y = 7

Answer 1

http://www.algebra.com/algebra/homework/coordinate/Types-of-systems-inconsistent-dependent-independent.lesson

Answer 2

independent, they will both have different slopes, meaning they will intersect once on the graph, and have one solution

Answer 3

Danj, i'm so sorry to ask you this, but I have no clue what i'm doing when I see this question...

Answer 4

10x + 2y = 14

is the same line as 5x + y =7

Multiply the equation by 2, it is the same line, not independent

Answer 5

Ahh

Answer 6

-15x - 3y = -6

the x and y coefficients -15 and -3, are -3 times the x and y coeffiecents in the original line.

the two will be PARALLEL lines. No Solution, and Inconsistent

Answer 7

5x + y = -7

same as the last one, the coefficients on the X and Y are a multiple of the original line, this time just 1 times the original.

Parallel Lines, No Solutions, Inconsistent

Answer 8

So the last one is the answer?

Answer 9

Right, there is not number you can multiply 6x+2y=7 by to get the first equations coefficients on X and Y,
If you solved these two equations, you will get one unique answer, the intersection point of the two lines (x,y)
This is a consistent, independent, one solution, system.

Answer 10

Thank you!

Answer 11

review that linked page in the first response, it will give you all that info again.