Question

Solve on the interval [0, 2pi):

2sin^2 x-3sin x +1=0

I think it is C.

Please explain answer. Thank you!

Answer 1

you can factor your quadratic (in terms of sin) there

Answer 2

\[2 \sin^2(x)-2\sin(x)-\sin(x)+1=0 \\ 2\sin(x)[\sin(x)-1]-1[\sin(x)-1]=0 \\ [\sin(x)-1][2 \sin(x)-1]=0\]
set both equal to zero and solve

Answer 3

@freckles

sinx = 1 ----> x = π/2
sinx = 1/2 ----> x = π/6, 5π/6

Answer: C

Answer 4

@freckles is that right?

Answer 5

sounds great
:)