Mathematics
7 Online
OpenStudy (anonymous):
Given right triangle ABC.
In the given right triangle, find the length of the hypotenuse, AB, if BC = 6 and AC = 5.
sqrt 36
sqrt 61
sqrt 11
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OpenStudy (sleepyjess):
Do you know the pythagorean theorem?
OpenStudy (anonymous):
a^2 + b^2 = c^2
OpenStudy (anonymous):
6^2 + 5^2 = c^2
OpenStudy (anonymous):
take it from there M'lady
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OpenStudy (anonymous):
so sqrt 11?
OpenStudy (sleepyjess):
No, what is \( 6^2\)?
OpenStudy (anonymous):
wait i always think its plus lol
OpenStudy (anonymous):
to the power it means the number times itself
OpenStudy (anonymous):
so 6^2 means 6 * 6
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OpenStudy (sleepyjess):
Here is the pythagorean theorem: \(\sf a^2+b^2=c^2\). Substitute in 6 for a, and 5 for b, then solve.
OpenStudy (sleepyjess):
Ok, so you are confused on exponents?
x^2 means x*x
x^3 means x*x*x
etc
OpenStudy (anonymous):
In many cases jess you won't be able to display a perfect perfect power so it's important that she realizes ^ is "to the power of"
OpenStudy (sleepyjess):
What do you mean a perfect perfect power?
OpenStudy (anonymous):
ok got that point lol thnx
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OpenStudy (anonymous):
I meant to only put one perfect my bad.
OpenStudy (sleepyjess):
Ok, so what do you get once you add 6^2 + 5^2?
OpenStudy (anonymous):
It means that you won't always be able to make a fancy version of 6^2 and so she'll need to know what ^ means
OpenStudy (sleepyjess):
Oh, like this: \(\sf 6^2\) vs this? 6^2
OpenStudy (anonymous):
yea
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OpenStudy (sleepyjess):
ok :)
OpenStudy (anonymous):
6^2 = 36
5^2 = 25
36 + 25 = ?
OpenStudy (anonymous):
equalllllll....????????
OpenStudy (anonymous):
Basic math hereeeee
OpenStudy (anonymous):
61
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OpenStudy (anonymous):
there you go
OpenStudy (anonymous):
now
OpenStudy (anonymous):
square root of 61 isssss?
OpenStudy (sleepyjess):
Put into a calculator \(\sqrt{61}\)
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OpenStudy (sleepyjess):
That works too
OpenStudy (anonymous):
as a calculator I mean
OpenStudy (anonymous):
thnx
OpenStudy (sleepyjess):
So, in the end we have \(\sf\sqrt{61}\approx 7.8\)
OpenStudy (anonymous):
tada~