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Mathematics 10 Online
OpenStudy (darkbluechocobo):

Help with Trig practice problem

OpenStudy (darkbluechocobo):

OpenStudy (darkbluechocobo):

so to start a^2+7^2=8^2

OpenStudy (studygurl14):

Do you know the Pythagorean Theorem and how to use it to find the third side length?

OpenStudy (darkbluechocobo):

Yes

OpenStudy (studygurl14):

Yeah, what you have is correct. Solve for a.

OpenStudy (darkbluechocobo):

it would equal the sqrt15

OpenStudy (studygurl14):

correct. Okay, do you know the trigonometric ratios of all the functions?

OpenStudy (darkbluechocobo):

well question would it be 3qrt5?

OpenStudy (darkbluechocobo):

instead of sqrt15?

OpenStudy (studygurl14):

No. It would be \(\sqrt{15}\)

OpenStudy (darkbluechocobo):

Ok I was wondering

OpenStudy (darkbluechocobo):

so first is sin which is oppsite of hyp

OpenStudy (studygurl14):

Do you know sin, cos, tan, csc, sec, cot?

OpenStudy (darkbluechocobo):

mhm

OpenStudy (studygurl14):

yeah, opposite over hypotenuse. So what is that?

OpenStudy (darkbluechocobo):

so 8/sqrt15

OpenStudy (studygurl14):

Not quite. Flip them.

OpenStudy (darkbluechocobo):

oopsie sqrt15/8

OpenStudy (studygurl14):

Right. You found the ratio for csc though. :) \(\large\sin\theta=\Large\frac{8}{\sqrt{15}}\) \(\large\csc\theta=\Large\frac{\sqrt{15}}{8}\)

OpenStudy (studygurl14):

Now do cos.

OpenStudy (darkbluechocobo):

aha yay

OpenStudy (darkbluechocobo):

so 7/8 is what cos is

OpenStudy (darkbluechocobo):

and question dont you ahve those flipped wasnt sin sqrt15/8?

OpenStudy (darkbluechocobo):

and now for sec is 8/7?

OpenStudy (studygurl14):

yep. cos is 7/8 and sec is 8/7

OpenStudy (studygurl14):

And thanks for catching that. You're correct. I do have them backwards, hah

OpenStudy (darkbluechocobo):

question, i thought it is illegal to have sqrts in the denominator s:

OpenStudy (studygurl14):

It's not illegal, but it is frowned upon. It depends on the teacher. If you want to be safe, we can change it so that the denominator doesn't have a radical. Do you want to do that?

OpenStudy (darkbluechocobo):

Yes

OpenStudy (studygurl14):

Okay.

OpenStudy (darkbluechocobo):

so \[\frac{ 8 }{ \sqrt15 }*\frac{ \sqrt15 }{ \sqrt15 }=8\sqrt15/15\]

OpenStudy (darkbluechocobo):

\[\frac{ 8\sqrt15 }{ 15 }\]

OpenStudy (studygurl14):

\(\sf\Large\color{blue}{NICE\ JOB!}\) \(\large\sin\theta=\Large\frac{\sqrt{15}}{8}\) \(\large\csc\theta=\Large\frac{8}{\sqrt{15}}\rightarrow\frac{8\sqrt{15}}{15}\) \(\large\cos\theta=\Large\frac{7}{8}\) \(\large\sec\theta=\Large\frac{8}{7}\)

OpenStudy (studygurl14):

Now tan.

OpenStudy (darkbluechocobo):

woop

OpenStudy (darkbluechocobo):

sqrt15/7

OpenStudy (darkbluechocobo):

and 7sqrt15/15

OpenStudy (studygurl14):

Excellent job!

OpenStudy (darkbluechocobo):

lel that was easier than expected

OpenStudy (studygurl14):

:)

OpenStudy (darkbluechocobo):

aha

OpenStudy (darkbluechocobo):

Thank you for going through this :D

OpenStudy (studygurl14):

You're absolutely welcome. It was a pleasure working with you! \(\large\color{blue}{\ddot\smile}\)

OpenStudy (darkbluechocobo):

take my fan :p

OpenStudy (studygurl14):

Huh?

OpenStudy (darkbluechocobo):

loool I fanned you basically is what i meant :p

OpenStudy (studygurl14):

Oh, sorry. I figured, but I didn't see the notification until I refreshed. Thank you.

OpenStudy (darkbluechocobo):

Mhm :3

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