Question

Help with trig identities practice problem

Answer 1

\[\cot \theta \frac{ 2 }{ 3 } and \csc \theta>0,find \csc \theta \]

Answer 2

so cot is positive and so is csc

Answer 3

It's a question of which quadrant the terminal side is. There is only one quadrant in which sin and tan are>0

Answer 4

use this
\(1+cot^2\theta=csc^2\)

Answer 5

would that be quadrant 1?

Answer 6

If you wonder, it comes from \(sin^2\theta + cos^2\theta =1\) dividing it by \(sin^2\theta\)

Answer 7

and cot(2/3^2) 4/9+1= 13/9=csc^2?

Answer 8

wait i think i did that wrong

Answer 9

It is. Now draw an angle with adj/hyp = 2/3. Pythagorean, and solve.
You can also use the identities myko supplied, but you do have to know which quadrant you're in.

Answer 10

\(1+(2/3)^2=csc^2\)

Answer 11

i got 2.099

Answer 12

well exactly i did cot(2/3^2)

Answer 13

or do i just square 2/3?

Answer 14

problema states \(cot^2(\theta)\)=2/3 right?
if so, then square 2/3