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Mathematics 10 Online
OpenStudy (anonymous):

(8^2)^6

OpenStudy (dtan5457):

Pemdas Solve the parenthesis first, then ^6

Directrix (directrix):

@loveeaj22 What are the instructions for this problem?

OpenStudy (studygurl14):

You can also mutliply the exponents in and out of the parenthesis. \(\large 8^{2\times6}\)

Directrix (directrix):

And, you can express the answer as a power of 2. We need to know the instructions for the problme.

OpenStudy (studygurl14):

Yeah @loveeaj22 you may only have to simplify, not actually solve.

OpenStudy (studygurl14):

What @Directrix says

OpenStudy (anonymous):

do i add the exponents or multiply ?

OpenStudy (dtan5457):

You would multiply, because it's an exponent to an exponent \[(y^x)^x=y^{x \times x}\]

OpenStudy (anonymous):

the instructions are to simplify the problem

OpenStudy (dtan5457):

Where as \[y^x \times y^x=y^{x+x}\]

OpenStudy (anonymous):

ok @dtan5457 so it would be 64^12 ?

OpenStudy (mathstudent55):

No. Don't change the 8. Just multiply the exponents.

OpenStudy (anonymous):

so 8^12 @mathstudent55 ?

OpenStudy (mathstudent55):

Yes.

OpenStudy (anonymous):

thanks @mathstudent55 @dtan5457 @studygurl14 && @Directrix

OpenStudy (mathstudent55):

Each of the lines following the problem is a correct answer: \((8^2)^6\) \(= 8^{2 \times 6} = 8^{12} \) \(= 64^6\) \(= ((2^3)^2)^6 = 2^{36}\)

OpenStudy (mathstudent55):

You're welcome.

Directrix (directrix):

That is what I think the answer is intended to be.

OpenStudy (mathstudent55):

Of course, you can multiply it out and find a number for the answer.

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