(8^2)^6
Pemdas Solve the parenthesis first, then ^6
@loveeaj22 What are the instructions for this problem?
You can also mutliply the exponents in and out of the parenthesis. \(\large 8^{2\times6}\)
And, you can express the answer as a power of 2. We need to know the instructions for the problme.
Yeah @loveeaj22 you may only have to simplify, not actually solve.
What @Directrix says
do i add the exponents or multiply ?
You would multiply, because it's an exponent to an exponent \[(y^x)^x=y^{x \times x}\]
the instructions are to simplify the problem
Where as \[y^x \times y^x=y^{x+x}\]
ok @dtan5457 so it would be 64^12 ?
No. Don't change the 8. Just multiply the exponents.
so 8^12 @mathstudent55 ?
Yes.
thanks @mathstudent55 @dtan5457 @studygurl14 && @Directrix
Each of the lines following the problem is a correct answer: \((8^2)^6\) \(= 8^{2 \times 6} = 8^{12} \) \(= 64^6\) \(= ((2^3)^2)^6 = 2^{36}\)
You're welcome.
That is what I think the answer is intended to be.
Of course, you can multiply it out and find a number for the answer.
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