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Mathematics 19 Online
OpenStudy (darkbluechocobo):

Help with practice problems for trig

OpenStudy (darkbluechocobo):

OpenStudy (freckles):

@DarkBlueChocobo you should be able to do this \[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)} \\ \cot(\theta)=\frac{\cos(\theta)}{\sin(\theta)} \\ \csc(\theta)=\frac{1}{\sin(\theta)} \\ \sec(\theta)=\frac{1}{\cos(\theta)}\]

OpenStudy (freckles):

just enter in what is given and simplify the quotient

OpenStudy (darkbluechocobo):

\[\frac{ 2\sqrt5 }{ 5 }\div-\frac{ \sqrt5 }{ 5 } \]

OpenStudy (freckles):

ok looks like you are doing cot first

OpenStudy (darkbluechocobo):

Yes, so is that all s: one moment let me copy that into my notes

OpenStudy (freckles):

If these identities weren't known to you before when we doing those questions then I understand I a little more why you were confused...

OpenStudy (darkbluechocobo):

alright sorry I didnt see that list before s:

OpenStudy (darkbluechocobo):

so would cot=-5

OpenStudy (freckles):

\[\frac{2 \sqrt{5}}{5} \div - \frac{\sqrt{5}}{5} \\ -\frac{2 \sqrt{5}}{5} \cdot \frac{5}{\sqrt{5}}=-2\]

OpenStudy (darkbluechocobo):

but I thought you cant have a sqrt in the denominator?

OpenStudy (darkbluechocobo):

oh wait in cancels it

OpenStudy (darkbluechocobo):

so then just switch the equation for tan so \[\frac{ \sqrt5 }{ 5 }\div \frac{ 2\sqrt5 }{ 5 }\]

OpenStudy (freckles):

well on my previous thread I did say tan and cot are just reciprocals of one another

OpenStudy (freckles):

just flip the -2

OpenStudy (freckles):

cot(theta)=-2 tan(theta)=-1/2

OpenStudy (freckles):

or you can do all that work

OpenStudy (freckles):

either way

OpenStudy (darkbluechocobo):

Aha yes i just got that since its the reciprocal

OpenStudy (freckles):

csc(theta) and sin(theta) are also reciprocals of one another sec(theta) and cos(theta) are reciprocals of one another

OpenStudy (darkbluechocobo):

\[1\div \frac{ \sqrt5 }{ 5 }\]

OpenStudy (darkbluechocobo):

is this 1 over sin or divided by?

OpenStudy (freckles):

\[\csc(\theta)=\frac{-5}{\sqrt{5}}\] just flip

OpenStudy (freckles):

rationalize the denominator

OpenStudy (freckles):

1/(a/b) means to flip a/b so 1/(a/b)=b/a

OpenStudy (darkbluechocobo):

and then for sec you flip it back?

OpenStudy (freckles):

no for sec just flip cos

OpenStudy (freckles):

for csc we will flip sin for sec we will flip cos

OpenStudy (darkbluechocobo):

so sec=\[-\frac{ 5 }{ 2\sqrt5 }\]

OpenStudy (freckles):

why does sec turn neg?

OpenStudy (freckles):

finding a number 's reciprocal doesn't involve altering the sign

OpenStudy (freckles):

unless someone tells you to find the opposite reciprocal

OpenStudy (darkbluechocobo):

Sorry i combined the - from sin

OpenStudy (freckles):

if cos is pos then sec is pos if sec is pos then cos is pos

OpenStudy (darkbluechocobo):

I miss look a lot of times sorry

OpenStudy (freckles):

it is okay

OpenStudy (darkbluechocobo):

Thank you for all the help again though

OpenStudy (freckles):

i just hope you are actually understanding things that I'm saying

OpenStudy (darkbluechocobo):

Yes now that I have that list of things its a lot clearer i need to look back in my book to see if there is a list like that

OpenStudy (freckles):

there should be though I could be mistaken

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