Help with practice problems for trig
@DarkBlueChocobo you should be able to do this \[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)} \\ \cot(\theta)=\frac{\cos(\theta)}{\sin(\theta)} \\ \csc(\theta)=\frac{1}{\sin(\theta)} \\ \sec(\theta)=\frac{1}{\cos(\theta)}\]
just enter in what is given and simplify the quotient
\[\frac{ 2\sqrt5 }{ 5 }\div-\frac{ \sqrt5 }{ 5 } \]
ok looks like you are doing cot first
Yes, so is that all s: one moment let me copy that into my notes
If these identities weren't known to you before when we doing those questions then I understand I a little more why you were confused...
alright sorry I didnt see that list before s:
so would cot=-5
\[\frac{2 \sqrt{5}}{5} \div - \frac{\sqrt{5}}{5} \\ -\frac{2 \sqrt{5}}{5} \cdot \frac{5}{\sqrt{5}}=-2\]
but I thought you cant have a sqrt in the denominator?
oh wait in cancels it
so then just switch the equation for tan so \[\frac{ \sqrt5 }{ 5 }\div \frac{ 2\sqrt5 }{ 5 }\]
well on my previous thread I did say tan and cot are just reciprocals of one another
just flip the -2
cot(theta)=-2 tan(theta)=-1/2
or you can do all that work
either way
Aha yes i just got that since its the reciprocal
csc(theta) and sin(theta) are also reciprocals of one another sec(theta) and cos(theta) are reciprocals of one another
\[1\div \frac{ \sqrt5 }{ 5 }\]
is this 1 over sin or divided by?
\[\csc(\theta)=\frac{-5}{\sqrt{5}}\] just flip
rationalize the denominator
1/(a/b) means to flip a/b so 1/(a/b)=b/a
and then for sec you flip it back?
no for sec just flip cos
for csc we will flip sin for sec we will flip cos
so sec=\[-\frac{ 5 }{ 2\sqrt5 }\]
why does sec turn neg?
finding a number 's reciprocal doesn't involve altering the sign
unless someone tells you to find the opposite reciprocal
Sorry i combined the - from sin
if cos is pos then sec is pos if sec is pos then cos is pos
I miss look a lot of times sorry
it is okay
Thank you for all the help again though
i just hope you are actually understanding things that I'm saying
Yes now that I have that list of things its a lot clearer i need to look back in my book to see if there is a list like that
there should be though I could be mistaken
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