Someone refresh me on finding vertical and horizontal asymptotes of rational functions.
In the forms \[y=\frac{ a }{ x-h }+k\]
and \[y=\frac{ ax+b }{ cx+d }\]
@Nnesha
Someone just give me an example of anything each in that form..
Ok, i'll give the example.. \[y=\frac{ 3 }{ x-2 }+5\]
If im not mistaken, in that form... x=h y=k ?
for range and domain?
@Kainui In your example, is the domain all real numbers except for 3.8? And range as well?
Just play with it, move the sliders around.
The function will have a vertical asymptote at a value x=a, if \[\lim_{x \rightarrow a^-}(x) = \pm \infty \]\[\lim_{x \rightarrow a^+}f(x) = \pm \infty\]\[\lim_{x \rightarrow a}(x) = \pm \infty\]
I know A doesn't really affect the domain and range, I just want to know if for your specific example if I had the domain and range correct
Dan, can you just check for my example I gave. Is the domain all real numbers except for 2, and range is all except for 5?
That should clear it up for that form
The function will have a horizontal asymptote at Y=# if the function approaches a value # as x goes to + or - infinity.
How would I write that? domain= \[(-\infty,2)(2,\infty)\]
Sorry, was afk
Yeah, Domain of f(x) is all x such that x does not equal h
\[[~x ~| ~~x ~\epsilon ~R ,~ and ~x \neq h]\]
Looks good. What about for something in the form \[y=\frac{ ax+b }{ cx+d }\]
Wasn't there a specific formula to get domain and range for that?
Not in my notes..
hmm
Oh. y=a/c x=-d/c right?
For the domain, the denominator cant be zero, so \[cx+d \neq0~~~~or~~~~x \neq \frac{ -d }{ c }\]
the domain would be all real numbers x, except x cant be -d/c
The range would be all the Y values you get from the domain
\[y=\frac{ 5x+2 }{ 7x+6 }\]
So for this domain would be all except for -6/7?
7x + 6 cant be 0
-6/7 times 7=-6
-6+6=0
right, x can't be -6/7, take limit from right and left, one is +infinity one is -infinity
Hmm ok. And for range...just all except for 5/7?
yeah
Looks clear now, thanks again dude
let x go to infinity, first divide everything by x
\[\lim_{x \rightarrow \infty}\frac{ 5 + \frac{ 2 }{ x } }{ 7+\frac{ 6 }{ x } } = \frac{ 5 }{ 7 }\]
horizontal axmptopeas, i cant spell it
as x goes to infinity , y goes to 5/7
so if on a test, I shouldn't write all real numbers except for #?
D: { x vertical line x not equal a}
all x, such that x does not equal #, the number being the vertical asmyptote
i see
lol damn I hope that is not necessary. only in alegebra2/trig...never seen this in my life
Definitely gonna use that algebra sheet, thanks
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