Calculate the mass (in grams) of silver in 10.0 grams of silver sulfide, Ag2S.
Step 1: Calculate the molar mass of Ag2S
What is the molecular weight of Ag (silver)?
100?
It's 108 g/mol, Ag has a subscript of 2, theirs two amounts of Ag which means you multiply the mass by 2 108 g/mol*2=216 grams`
ohhhhh thank you!
So, we have Ag2 which equals to 216 216 + sulfur's molecular weight sulfur weighs 32 so the molar mass of Ag2S is 216 + 32
Makes sense?
you lost me! lol
87.09%
Ok, to calculate the mass (in grams) of silver in 10.0 grams of silver sulfide, we need to convert 10 grams silver sulfide sample to mols, then multiply the mol of Ag2S by molar ratio of Ag2 there's 1 mol of Ag2S by 2 mols of Ag That means we need to convert the sample to mols \(10.0~g~Ag2S~*(\Large\frac{1 mol Ag_2S}{ 247.9 g Ag2S})*(\Large \frac{2~mol~Ag} {1 mol Ag2S})\)= ?~mol Ag after you get the mol of Ag, multiply it by the mass of Ag
thank you so much!
No problem, you may close this question after you're done with it =)
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