OpenStudy (anonymous):

Calculate the mass (in grams) of silver in 10.0 grams of silver sulfide, Ag2S.

2 years ago
OpenStudy (zale101):

Step 1: Calculate the molar mass of Ag2S

2 years ago
OpenStudy (zale101):

What is the molecular weight of Ag (silver)?

2 years ago
OpenStudy (anonymous):

100?

2 years ago
OpenStudy (zale101):

It's 108 g/mol, Ag has a subscript of 2, theirs two amounts of Ag which means you multiply the mass by 2 108 g/mol*2=216 grams`

2 years ago
OpenStudy (anonymous):

ohhhhh thank you!

2 years ago
OpenStudy (zale101):

So, we have Ag2 which equals to 216 216 + sulfur's molecular weight sulfur weighs 32 so the molar mass of Ag2S is 216 + 32

2 years ago
OpenStudy (zale101):

Makes sense?

2 years ago
OpenStudy (anonymous):

you lost me! lol

2 years ago
OpenStudy (anonymous):

87.09%

2 years ago
OpenStudy (zale101):

Ok, to calculate the mass (in grams) of silver in 10.0 grams of silver sulfide, we need to convert 10 grams silver sulfide sample to mols, then multiply the mol of Ag2S by molar ratio of Ag2 there's 1 mol of Ag2S by 2 mols of Ag That means we need to convert the sample to mols \(10.0~g~Ag2S~*(\Large\frac{1 mol Ag_2S}{ 247.9 g Ag2S})*(\Large \frac{2~mol~Ag} {1 mol Ag2S})\)= ?~mol Ag after you get the mol of Ag, multiply it by the mass of Ag

2 years ago
OpenStudy (anonymous):

thank you so much!

2 years ago
OpenStudy (zale101):

No problem, you may close this question after you're done with it =)

2 years ago
Similar Questions: