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Mathematics 20 Online
OpenStudy (anonymous):

Write the equation of the line, in point-slope form and slope-intercept form, that contains the points (-2, -1 ) and (2, 1 ).

OpenStudy (anonymous):

OpenStudy (zale101):

It's called the slope formula because you are solving for the slope

OpenStudy (anonymous):

actually its y1-y2

OpenStudy (zale101):

Slope formula is m=\(\Large \frac {y_2-y_1}{x_2-x_1}\)

OpenStudy (zale101):

Apply the giving to points there for the slope :)

OpenStudy (anonymous):

ok ok and ok

OpenStudy (zale101):

after solving for the slope apply to the point slope formula plus one of the giving points \(y-y_1=m(x-x_1)\)

OpenStudy (anonymous):

WHOAH WHOAH WHOAH

OpenStudy (anonymous):

WHAT HAPPENED TO Y2??

OpenStudy (zale101):

What happened to y2, what do you mean? It's p[art of the slope formula for you to apply the given y value there.

OpenStudy (zale101):

part*

OpenStudy (anonymous):

oh i got confused cuz you only said y-y1

OpenStudy (zale101):

for the point slope, the x1,y1 means that you are plugging in values to those points, set aside x,y

OpenStudy (zale101):

Do the first step. Can you solve for the slope with using the formula i given to you? :)

OpenStudy (anonymous):

"gave to you" sorry had to correct you there

OpenStudy (anonymous):

Wait im still confused whats X and Y in the second part?

OpenStudy (zale101):

You are given the points (-2, -1 ) and (2, 1 ) \(slope=\Large\frac{y_2-y_1}{x_2-x_1}\) Let's say \((x_1,y_1)\)= (-2, -1 ) is the first point \((x_2,y_2)\)=(2,1) is the second point Plug those in \(slope=\Large\frac{(1)-(-1)}{2-(-2)}\)=?

OpenStudy (anonymous):

both the negatives would become positives and the minus would become a plus then you add them together and it turns into 2/4

OpenStudy (anonymous):

btw how you do the line thing for 1-(-1)/2-(-2)

OpenStudy (zale101):

yes, and if you reduced the fraction by the divisions of 2 \(\Large \frac{2\div2}{4\div2}\)=\(\Large \frac{1}{2}\) The slope is 1/2 Now, we have the point slope formula. y-y1=m(x-x1) Plug 1/2 for m and I will choose this point (2, 1 ) as for x1,y1. Again, It doesn't matter what point to use.

OpenStudy (anonymous):

so what is x? we know x1 is 2 so is x -2?

OpenStudy (zale101):

x1,y1 is not the same as x1,y1 we used for the slope formula But anyways, x1,y1 is (2, 1 ) therefore x1 is 2 and y1 is 1

OpenStudy (zale101):

i chose any point slope i wanted for x1,y1 in the y-y1=m(x-x1) formula. I chose (2,1)

OpenStudy (anonymous):

look man im not talking about what is x1 im talking about what is the regular X in the equation y-y1=m(x-x1)

OpenStudy (zale101):

The regular x and the regular y, those what determine a graph to become a function meaning set of rules. y=mx+b m and b are numbers, y and x, is any number that is plugged for x determines y. Makes sense? Example. This equation y=2x+6 see where y and x don't have numbers?

OpenStudy (anonymous):

ohhhhhh ok!!!

OpenStudy (anonymous):

look i can work it out later can you tell me what this is?

OpenStudy (zale101):

So, back to your question. Have you plugged the numbers yet? m=1/2 (x1,y1)=(2,1) or if you want (-2,-1)

OpenStudy (zale101):

You mean, to tell you the answer?

OpenStudy (anonymous):

i remember how to do it now but its gettin late and i really need this plz!!

OpenStudy (zale101):

I'm sure you can do it Diamond!! =D

OpenStudy (anonymous):

come one man

OpenStudy (anonymous):

come on*

OpenStudy (anonymous):

plz

OpenStudy (zale101):

Come on diamond, i know you can. You are almost near to solving the question. All you have to do is plug and solve for y and you are done! :D

OpenStudy (anonymous):

so 1/2+2x=y?

OpenStudy (zale101):

If i tell you the answer, that means my goal in tutoring you is gone for nothing :( My goal was to walk you through.

OpenStudy (zale101):

|dw:1421724871370:dw| Here, i plugged it for you. Can you now distribute and solve for y?

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