Question

Dr. Wang is jogging down the sidewalk at a speed of 4.20m/s. Her husband realizes that she forgot her lunch bagels, so he runs to the window of their house, which is a height of 35.0m above the street level and directly above the sidewalk, to throw them to her. He throws them horizontally at a time 7.50s after Dr wang has passed below the window, and she catches them on the run. You can ignore air resistance. W/what initial speed must Dr Wang's husband throw the bagels so she can catch them before they hit the ground? Where is Dr Wang when she catches the bagels?

Answer 1

Let Dr. Wang and her lunch bagels meets at a common point after time t.
Distance travelled =4.2(7.50+t)
In the same time vertical distance travelled=35 m
t =sqrt(2*35/9.8)=0.85 Sec
Distance travelled by Dr. Wang=4.2(7.50+0.85)= 35.05m