Determine the number of possible triangles, ABC, that can be formed given B = 45°, b = 4, and c = 5.

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Question

Determine the number of possible triangles, ABC, that can be formed given B = 45°, b = 4, and c = 5.


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anonymous · Answer

@dtan5457

anonymous · Answer

@Miracrown

mathmath333 · Answer

u need to use the sin rule and find $\angle C$

mathmath333 · Answer

$\large\tt \begin{align} \color{black}{\dfrac{\sin B}{b}=\dfrac{\sin C}{c}\hspace{.33em}\~\}\end{align}$

mathmath333 · Answer

oh wait the second 
$\angle C=62 ~~and~~(180-62)=118$

so the $62+45+\angle A=180$

$118+45+\angle A=180$


so the $two$ triangles are does possible here

triciaal · Answer

@mathmath333 I was thinking about a right isosceles triangle so it would be only one. I guess you have where one angle is 45 and not a right angle

mathmath333 · Answer

how can right iscoceles triangle can form since $\angle C=62~and ~118$

triciaal · Answer

@mathmath333   you have where one angle is 45 and not a right angle so you have 62 and 118

mathmath333 · Answer

i have B->45 ,C-> 62 and A-.73

and B->45,C->118 and A-> 18

two possiblities

anonymous · Answer

thnx