Question

Simplify and write using positive exponents

Answer 1

\[\frac{ 3x^{-4}y^5 }{ (2x^3y^{-7})^{-2} }\]

Answer 2

\[\frac{3x^{-4}y^5}{2^{1(-2)}x^{3(-2)}y^{-7(-2)}} \text{ is what I would do first }\]

Answer 3

sounds good

Answer 4

then use quotient rule for the variables you have there

Answer 5

x^a/x^b=x^(a-b)

Answer 6

you want to tell me what you have have using that quotient rule for exponents

Answer 7

oh ok nevermind
I think @KendrickLamar2014 simplified it for you

Answer 8

i'm not sure how he got there though

Answer 9

Oh sorry @freckles

Answer 10

@Nnesha

Answer 11

\[\frac{3x^{-4}y^5}{2^{-2}x^{-6}y^{14}} \\ \frac{3}{2^{-2}} \cdot \frac{x^{-4}}{x^{-6}} \cdot \frac{y^5}{y^{14}} \\ \text{ use the quotient rule } \frac{x^a}{x^b}=x^{a-b} \\ \frac{3}{2^{-2}} x^{-4-(-6)}y^{5-14}\]

Answer 12

now to get rid of negative exponents use one of the following:
\[\frac{1}{x^{-a}}=x^{a} \\ x^{-a}=\frac{1}{x^{a}}\]

Answer 13

So the first one is 3/4
2nd is x^2
3rd is 1/y^9

?

Answer 14

well the first one isn't 3/4

Answer 15

it is actually 3*2^2=3(4)=12

Answer 16

and yes to the rest

Answer 17

\[3(2^2) x^2 \frac{1}{y^9} \\ 3(4)\frac{x^2}{y^9} \\\]

Answer 18

Oh right, negative exponent in denominator=positive in numerator

Answer 19

it is the same result mr lamar got

Answer 20

you have any questions

Answer 21

Nope, got it now. Just gotta remember that any negative exponent numerator or denominator, goes to the opposite side. With that knowledge, this problem is easy :)