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Let f(x) = x^2 + 6 and g(x) = ((x+8)/(x)) Find (g of f)(-7)
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(g of f)(-7) => g(f(-7)), start off by solving for g(f(x)) :)
-((55)/(7)) ((384)/(7)) ((295)/(49)) ((63)/(55)) These are the given answers and I believe it's ((384)/(7))
What is g(f(x)) or (g of f)(x)?
hum, I'm not sure.
It just means plug in f(x) where ever there is an x in g(x) :P
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I was doing this earlier but I've been working a bunch of other problems so I came back to it and am a bit lost. oh okay thank you. hum
g(x^2 + 6 = ((x+8)/(x))
\[g(f(x)) \implies \frac{ (x^2+6)+8 }{ (x^2+6) }\]
Does that make sense?
ohhh I see you're just combining them
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Plugging f(x) into g(x)
yea okay. So then from there I just times that by -7?
Yes, plug in -7 into the x's :)
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