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Find an equation of a plane through the point (2, 1, 2) which is parallel to the plane 1x−2y−4z=7 in which the coefficient of x is 1.
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you need a `point` and a `normal vector` to write the equation of plane
a normal vector is <1,-2,-4>
you also have a point through which the plane goes whats stopping you from writing the equation of plane
ah I just don't get how to write it given those 2 things
|dw:1421731911992:dw|
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Say P(x, y, z) is any other point on the plane : |dw:1421731967811:dw|
join the given point to P : |dw:1421732006396:dw|
would you agree that the both vectors shown are perpendicular ?
yes
that means the dot product must be 0 ?
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yes
(x-2, y-1, z-2) . (1, -2, -4) = 0 thats the equation of plane
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