Find the approximate value of b in the triangle shown. 13 12 8 5
https://clackamasweb.owschools.com/media/g_geo_ccss_2014/11/geo_10a_8_assess_media_2.gif
use cosine law, have an idea what is it ?
nope
:O
\(b^2=a^2+c^2-2ac~ \cos B\)
b2=12^2+10^2−2ac cosB ?
maybe u know it by its name "law of cosines"
no i really dont:( dont really have had time to learn it
its ok :) just memorize the formula and everything will be ok ur on the right track , u need to sub a and c as well like this http://prntscr.com/5uqic6
here u can see this link also http://www.mathsisfun.com/algebra/trig-cosine-law.html
i got 4 from it...
:O how?
12^2+10^2 - 2*12*10 cos 24 = 142
how do i get it be one of my options?
wait \(b^2= 12^2+10^2 - 2*12*10 cos 24 =24.74.....\) \(b=\sqrt(24.74.....)=4.97...\) almost 5 when u said 4 like it was the right answer but i waned to be sure about approximation value
ok thnx
eh np
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