Question

**WILL MEDAL**
Write the equation of the line, in point-slope form and slope-intercept form, that contains the points (-2, -1 ) and (2, 1 ).

Answer 1

slop or m= y2-y1/x2-x1 so we have: (2+2)/(1+1)=4/2=2

Answer 2

actually thats wrong

Answer 3

(PSF) Point slope form = \( y - y_1 = m(x - x_1) \)

(SIF) Slope-intercept form = y =mx + b

We need slope too.

Slope (m) = \( \frac{y_2 - y_1}{x_2 - x_1} \)

First find the slope.
(m) = \( \frac{y_2 - y_1}{x_2 - x_1} \)

Second use a point (2, 1 ) and insert it into the equation below. Also put your slope into the equation.

\( y - y_1 = m(x - x_1) \)

Last, convert \( y - y_1 = m(x - x_1) \) into slope intercept form.

Let me know what you have problems with.

Answer 4

MDoodler alright got to that y=1/2x

Answer 5

that is the quation Line right?

so we get m=2 so according to the Equation Line we have: y-2=2(x-1)

Answer 6

wrong y1 is 1

Answer 7

look @MDoodler i need point slope form

Answer 8

and i need it in slope intercept if i already got them tell me what they are @MDoodler

Answer 9

sorry ur right again: y-1=2(x-2)

Answer 10

1/2 is the slope not 2

Answer 11

and 1/2(x-2)=1/2x-1

Answer 12

slope = 1/2
Using the point (2,1)

\( y - y_1 = m( x - x_1) \)

Point slope form = \( y - 1 = \frac{1}{2}( x - 2) \)


Convert to slope- intercept
\( y - 1 = \frac{1}{2}( x - 2) \)

Answer 13

and point slope @MDoodler ?

Answer 14

yes sorry ur right m=1/2

Answer 15

i mean slope intercept* is y=1/2x?

Answer 16

correct?

Answer 17

\( y - 1 = \frac{1}{2}(x - 2) \)
\( y - 1 = \frac{1}{2}(x - 2) \)
\( y - 1 = \frac{1}{2}x - 1 \)
\( y = \frac{1}{2}x - 1 + 1 \)
\( y = \frac{1}{2}x + 0 \)
\( y = \frac{1}{2}x \)

correct

Answer 18

thx sooooo much!!