Question

I'll give medals!!


A sailor in a small sailboat encounters shifting winds.She sails 2.00km east, then 3.50km southeast, and then an additional distance in unknown direction. final position is 5.80km directly east of her starting point.

please show work so I can understand

Answer 1

5.80 km - 2.00 km = 3.80 km the you find the distance

The distance 3.80 km forms an angle of
45 deg with the distance 3.50 km southeast.


c = sqrt[3.80^2+3.50^2-2(3.80)(3.50)cos45deg...
c = 2.81 km

sinA/3.50 = sin 45 deg/2.81
A = arcsin[3.50(sin45/2.81)]
A = 61.7deg

45deg + 61.7 deg - 90 deg = 16.7 deg

So if you did this correctly, then out should get this answer: 2.81km, 16.7 deg east of north

Answer 2

I hope this helped!

Answer 3

thank you