Question

Help with trig practice problems

Answer 1

I believe that \[\Theta=\frac{ \pi }{ 4 } and \tan \theta=-1\]

Answer 2

use the identity


\(\large\tt \begin{align} \color{black}{\tan (\pi+x) =\tan x\hspace{.33em}\\~\\}\end{align}\)

Answer 3

Question what would x be ? something to solve for?

Answer 4

Also I found the reference angle by doing \[\frac{ 19\pi }{ 4 }-4\pi= \frac{ 3\pi }{ 4 }-\pi=-\frac{ \pi }{ 4 }\]

Answer 5

and then by finding the other part by doing \[\tan (\frac{ 19\pi }{ 4 })\]

Answer 6

which i got -1 by doing that

Answer 7

\(\large\tt \begin{align} \color{black}{
=\tan (\dfrac{19\pi}{4}) \hspace{.33em}\\~\\
=\tan (\dfrac{16\pi+3\pi}{4}) \hspace{.33em}\\~\\
=\tan (\dfrac{3\pi}{4}) \hspace{.33em}\\~\\
=\tan (\dfrac{4\pi-\pi}{4}) \hspace{.33em}\\~\\
=\tan (\dfrac{-\pi}{4}) \hspace{.33em}\\~\\
=-\tan (\dfrac{\pi}{4}) \hspace{.33em}\\~\\
=-1
}\end{align}\)




so \(\Huge -1\) is \(\Huge \checkmark\)

Answer 8

What about the \[-\frac{ \pi }{ 4 }\]

Answer 9

Did I do that correctly :p

Answer 10

its important to write in the form as i did

Answer 11

yes ur work seems correct !

Answer 12

Thank you for checking and about the the form do you mean

Answer 13

like tan(19pi/4+pi) I am confused

Answer 14

write it in the \(\huge tan (\fbox{-})\)

Answer 15

inside the box

Answer 16

Ahh ok