Question

Help with reference angles

Answer 1

so i know \[\tan \theta=-\sqrt3\]

Answer 2

and to find \[\theta'\]

Answer 3

\[\frac{ -10\pi }{ 3 }+4\pi\]

Answer 4

\(-\sqrt{3}\) is the final answer, you're done!

Answer 5

But I have to find \[\theta'\]

Answer 6

question doesn't ask you to find the reference angle

Answer 7

it only says to use the reference angle to evaluate tan(-10pi/3)

Answer 8

Im confused about this part cause you would get \[\frac{ 2\pi }{ 3 }\]

Answer 9

welp I have than that to select from though

Answer 10

yes subtract that from \(\pi \)

Answer 11

reference angle = \(\large \pi - \frac{2\pi}{3} = ?\)

Answer 12

so positive pi/3

Answer 13

Yep!

Answer 14

Could you assist me with one more

Answer 15

This one is just a true or false one, but

Answer 16

ok

Answer 17

A reference angle exists for the following angle: θ = -810°.-810+3(360)=270

Answer 18

But im confused would you subtract this by 180 because reference angles need to be between 0 and 90

Answer 19

yes i think 90 degrees is the reference angle for 270

Answer 20

so this would be true then

Answer 21

im not sure, some google results say 90 is reference angle and some say 90 cannot be a reference angle

Answer 22

@freckles

Answer 23

it is \(90\)

Answer 24

Yes but I believe we are unsure if 90 is a reference angle

Answer 25

http://www.mathwarehouse.com/trigonometry/reference-angle/finding-reference-angle.php

Answer 26

Ahh Isee

Answer 27

http://m.wolframalpha.com/input/?i=find+the+reference+angle+for+270+degrees&x=0&y=0

Answer 28

looks neat

Answer 29

if angle is on axis then the previous quadrant is considered i think

Answer 30

in this case the \(3rd\) quadrant

Answer 31

if you do either 360-270 or 270-180
you should get 90 deg for either one