Question

will medal picture below pls help thankyou

Answer 1

HI!!

Answer 2

Use Pythagoras theorem when you have a right triangle, with length of hypotenuse C and legs A and B.
\(C = \sqrt{A^2+B^2}\)
When A=B, this simplifies to
\(C = \sqrt{A^2+B^2}=\sqrt{A^2+A^2}=A\sqrt{2}\)
An example is shown below:

Answer 3

hey!!

Answer 4

to find the diagonal of a square, multiply the side by \(\sqrt 2\)

Answer 5

so it would be C?

Answer 6

or D

Answer 7

To help clarify:
\(\sqrt{a\times b}=\sqrt a \times \sqrt b\)
Example:
\(\sqrt{10}=\sqrt{5\times 2}=\sqrt 5 \times \sqrt 2\)

while
\(\sqrt{a^2\times b}=\sqrt {a^2} \times \sqrt b=a\times \sqrt b\)
Example
\(\sqrt{50}=\sqrt{25\times 2}=\sqrt {5^2} \times \sqrt 2=5\times \sqrt 2\)