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Chemistry 14 Online
OpenStudy (anonymous):

On changing concentration and Volume and the rate of reaction: I'm given a reaction: HCL added to excess CaCO3 in a flask Then a graph showing volume of CO3 and time

OpenStudy (anonymous):

|dw:1421789609427:dw| Why is it shaped like this? Then I'm told to draw the curve that I would obtain if I "double the volume of the HCl solution of HALF the concentration as in the example above used instead, with every other variable kept same" Explain why the shape of curve is different I suspect because its a second order reaction? Or is it something else?

OpenStudy (australopithecus):

http://www.chemguide.co.uk/physical/basicrates/experimental.html This should help

OpenStudy (australopithecus):

If you lower the reaction your initial rate is going to be slower because it will be less likely for your reactants to interact with each other in solution

OpenStudy (anonymous):

Uh... It doubles the volume and halves the concentration, could you explain why that would change the reaction rate at all?

OpenStudy (anonymous):

@Australopithecus

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