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Mathematics 24 Online
OpenStudy (anonymous):

Variable y varies directly with x2, and y = 196 when x = 7. Enter the constant of variation in the quadratic variation equation. y = x2

OpenStudy (jdoe0001):

\(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x \end{array}\\ \quad \\ y= 196\qquad x=7\qquad thus\qquad y={\color{red}{ n}}x^2 \iff 196={\color{red}{ n}}7\) so what would "n" be then? that is, "n" or the "constant of variation"

OpenStudy (jdoe0001):

hmm actaully should be squared....so \(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ y&={\color{red}{ n}}&x&\implies y={\color{red}{ n}}x \end{array}\\ \quad \\ y= 196\qquad x=7\qquad thus\qquad y={\color{red}{ n}}x^2 \iff 196={\color{red}{ n}}7^2\) so... what's "n" then?

OpenStudy (anonymous):

196?

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

I don't understand plz

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