The population of a city is growing at an average rate of 3% per year. In 1990, the population was 45 000. a) Write an equation that models the growth of the city. Explain what each part of the equation represents. b) Use your equation to determine the population of the city in 2007. c) Determine the year during which the population will have doubled. d) Suppose the population took only 10 years to double. What growth rate would be required for this to have happened?
Need help with part D
@allibricker12
@M,aliha
@maddie456
about 7%
here is for all 4. a) y=45000 (1 .03)^x b) 74 378 (approx.) c) by 2013 d) about 7%
c be 2014
I just need help with part d
how u get 7%
no i got 2013. and part d is 7%
do u get 2013
but how
I've taken this assignment. and just remember.
just help me with part d
please
@KamiBug
sorry :(.......dont know
ok np
Population at time t = Initial population*(rate)^time P(t) = A*b^t
I only need help with part d
rate of 3 percent per year b = 0.03
ok
p(t) = A*(0.03)^t Let t = 0 at 1990 , and t=t is the year after 1990, so in 1990 t=0 and A = 45000
sorry 1.03
so t be 1990
p(t) = 45000*(1.03)^t t=years after 1990
in 2007, t will be 2007 - 1990 = 17 t=17 in year 2007 calculate p(17) = 45000*(1.03)^(17)
oh ok
I will do it know
The population will have doubled when it is 90000 Solve 90000 = 45000(1.03)^t for t, remember t=years after 1990
IF th epopulation took 10 years to double, the growth rate would be? solve 90000 = 45000(b)^10 for the rate b.
good?
each question is just asking you to solve for different variables using the same equation
lol i just went back to read, i like @allibricker12 response. You say you need help, then the first reply is 7%, some help. lol how you get that?
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