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PLEASE HELP!! MEDAL!! Simplify the expression: k+1/k^2-6k-7
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\[\frac{ K + 1 }{ k ^{2} - 6k - 7}\]
We can first factor the denominator
k+1/(k-7)(k+1)
@Miracrown
Yes, that's right
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And we can cancel out k+1
So, after cancelling k+1, what does it become?
k-7??
Nope, it becomes 1/k-7
why it becomes 1??
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k+1=1*(k+1) k+1 is canceled out, but 1 is still there
i have another question is 3-x = 3??
No. What made you think that?
subtract 3 on both sides -x=0 so x=0
idk..its just i did the same thing as you did for cancelling out the k+1 and becomes 1
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x^2-4x+3/3-x
@Miracrown
3-x=-(x-3)
Once you cancel out x-3, the denominator becomes -1
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