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OpenStudy (anonymous):
@Nnesha
OpenStudy (xapproachesinfinity):
do you have any ideas how to start?
OpenStudy (xapproachesinfinity):
what did you do in class?
OpenStudy (anonymous):
not really
OpenStudy (xapproachesinfinity):
nothing at all
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OpenStudy (xapproachesinfinity):
don't remember what you did in class?
OpenStudy (anonymous):
No I meant I don't really know how to start off, that's what I'm trying to figure out
OpenStudy (anonymous):
is there a formula for it?
OpenStudy (xapproachesinfinity):
well im asking tell me anything you learned from class
OpenStudy (xapproachesinfinity):
about this
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OpenStudy (anonymous):
Oh well I dunno much about this really I just started the section about finding inverse functions
OpenStudy (xapproachesinfinity):
well what did you start with in class
there is no way your teacher/prof would assign you this if nothing is done in the class
OpenStudy (xapproachesinfinity):
in order for me to help i need to know what you know and what you don't
OpenStudy (anonymous):
ok well I just got done doing something like this f(x) = x -3 and g(x) = x-5) find f(g(5))
OpenStudy (xapproachesinfinity):
Okay i will assume you don't know anything yet about inverses!
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OpenStudy (anonymous):
That is what I said above
OpenStudy (anonymous):
@Nnesha
OpenStudy (xapproachesinfinity):
so what is an inverse function
basically and inverse it the operation we apply to undo some operation
say we have 5+(3)=8 to undo addition we take 8-3=5
i started with 5 added 3 to get outcome 8
the inverse of that is start with 8 subtract 3 to get back to 5
more formally if have y=x-3 the inverse is x=y+3 then i just do a trick and switch the variable x and y so y=x+3
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
so mine would be like x = (4y - 3)/(y)?
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OpenStudy (xapproachesinfinity):
no just follow...
OpenStudy (xapproachesinfinity):
now i have y=4/(x-1)
so according to what i just did
1/4 y=1/(x-1)
OpenStudy (xapproachesinfinity):
then i flip the fractions
i get 4/y =x-1 yes?
OpenStudy (xapproachesinfinity):
i did error in the previous one so pay attention to this one carefully
OpenStudy (xapproachesinfinity):
once we solve this one you should do the same to solve yours
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OpenStudy (anonymous):
ok...
OpenStudy (xapproachesinfinity):
\(\huge y=\frac{4}{x-1}\) this is our function okay
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
first:
multiply by 1/4 both sides
\(\huge \frac{1}{4}y=\frac{1}{4}\frac{4}{x-1}\)
OpenStudy (xapproachesinfinity):
following...
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OpenStudy (xapproachesinfinity):
so far okay?
OpenStudy (anonymous):
I think so
OpenStudy (xapproachesinfinity):
so i get \(\huge \frac{1}{4}y=\frac{1}{x-1}\) 4 canceled out (4/4=1)
OpenStudy (xapproachesinfinity):
now flip the fraction
\(\huge \frac{4}{y}=\frac{x-1}{1}\)
OpenStudy (xapproachesinfinity):
good!
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OpenStudy (xapproachesinfinity):
??
OpenStudy (xapproachesinfinity):
answer say no, yes say at least something
OpenStudy (anonymous):
lol I'm thinking
OpenStudy (xapproachesinfinity):
okay
OpenStudy (anonymous):
it looks okay I think...
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OpenStudy (xapproachesinfinity):
make sure
not just okay hehe
OpenStudy (xapproachesinfinity):
make sure you got it lol
OpenStudy (anonymous):
I think I got it
OpenStudy (xapproachesinfinity):
okay
OpenStudy (anonymous):
so for mine I have to multiply both sides by 4/3
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OpenStudy (xapproachesinfinity):
x-1/1 is just x-1 dividing by 1 does not change anything
so i get \(\huge \frac{4}{y}=x-1\)
OpenStudy (xapproachesinfinity):
no by -1/3 to cancel -3 on top of the left part fraction
OpenStudy (xapproachesinfinity):
why 4/3?
OpenStudy (xapproachesinfinity):
this needs some good algebra you know
OpenStudy (anonymous):
cause I thought you were flipping the denominator with the numerator and then multiplying both sides by it
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OpenStudy (xapproachesinfinity):
i first multiplied to cancel
then i flipped the both sides fractions so the equality stays correct
OpenStudy (xapproachesinfinity):
if i had 1/y=x/2 flipping would give me y=2/x yes
OpenStudy (xapproachesinfinity):
that's what i did to that fraction
OpenStudy (anonymous):
oh ok
OpenStudy (anonymous):
okay so multiply both sides by -1/3 and then I'll get
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OpenStudy (xapproachesinfinity):
back to our problem we are at \(\huge \frac{4}{y}=x-1\)
now i just need to add 1 to both sides to get \(\huge \frac{4}{y}+1=x\)
then i switch x and y to get
\(\huge \frac{4}{x}+1=y\)
OpenStudy (anonymous):
oh ok.
OpenStudy (xapproachesinfinity):
once you multiply you cancel -3 on top
you get -1/3 y=1/(x+4)
OpenStudy (xapproachesinfinity):
the one i just solved got me to
\(\huge y=\frac{4}{x}+1\) this the inverse i was looking for for my case
OpenStudy (xapproachesinfinity):
you follow the same steps to get there
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OpenStudy (anonymous):
*bangs head against wall* I might have missed something from the last chapter this seems so convoluted
OpenStudy (xapproachesinfinity):
well one thing you can't go straight solving problems without looking at you notes first
OpenStudy (xapproachesinfinity):
it does not work that way
OpenStudy (xapproachesinfinity):
yo need to study you notes and texbook before tackling any problem
OpenStudy (anonymous):
yea, I think I'm going back to my notes and try re-teaching myself some of this stuff and then I'll just use the stuff you've written as a reference for things
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OpenStudy (anonymous):
anyrate I thank you for the work you've done. not many people are patient enough to spend that much time trying to help someone so thank you
OpenStudy (xapproachesinfinity):
yes! need me just tag @x...
OpenStudy (anonymous):
ok
OpenStudy (xapproachesinfinity):
no problem! i could have just given you the answer but that won't help at all :)