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thanks
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@ganeshie8
\[(f\circ g)(4)\] like this ?
yep
\[(f\circ g)(4) = f(g(4))\]
start by evaluating \(g(4)\)
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\(g(x) = x^2+1\) \(g(4) = ?\)
g(4)=x^2+1?
replace x by 4
\(g(4) = 4^2 + 1 = ?\)
17
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Yes
\[(f\circ g)(4) = f(g(4)) = f(17) = ?\]
evaluate f(17) and you're done!
\(f(x) = x-8\) \(f(17) = ?\)
so its just 17
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nope you need to evaluate f(17) still
im lose and its even
you have \(f(x) = x-8\) simply replace \(x\) by \(17\) for \(f(17)\) : \(f(17) = 17-8 = ?\)
9
thanks so much!!!!
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thats right! please go through all the steps again
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