Question

thanks:)

Answer 1

@Michele_Laino

Answer 2

@iGreen

Answer 3

Please note that the first equation, namely:
\[x-2y-z=2\]
isn't consistent with the third equation, namely:
\[2x-4x-2z=3\]
so?

Answer 4

-2x-2z=3?

Answer 5

please note that first equation and third equation are incompatible each other

Answer 6

If I multiply both sides of the first equation by 2, I get:
\[2x-4y-2z=4\]
whereas the third equation tells us:
\[2x-4y-2z=3\]
do you think it is possible that?

Answer 7

yes?

Answer 8

or no?

Answer 9

no, please note that the same quantity can not be equal to 4 and to 3 at the same time

Answer 10

ow yea

Answer 11

what is your option then?

Answer 12

0,1,3?

Answer 13

please note that if a system has two or more equations which are not compatible, then that system admits no solutions

Answer 14

so its no solutions?

Answer 15

that's right!

Answer 16

thanks so much!!

Answer 17

thanks!