Write the explicit formula that represents the geometric sequence -2, 8, -32, 128. what am i supposed to do with the negative numbers? im so confused, please help
what is the common ratio?
just take a term and divide it by it's previous term to find
would it be 4?
well 8/-2 is -4 actually
\[a_n=ar^{n-1}\]
replace r with -4
so is that how you found the common ratio?
yep just take a term and divide it by it's previous term
xn = 8 × -2(n-1)?
8 x -4
\[a_n=a \cdot r^{n-1 } \\ r \text{ is common ratio number } \\ a \text{ is first term in the sequence }\]
so is that all you have to do? or do you ri==write out an equation for it?
\[a_n=a \cdot r^{n-1 } \\ r \text{ is common ratio number } \\ a \text{ is first term in the sequence }\] all you do is replace r with -4 and a with the first number in the sequence
do you see what your first number is in your sequence?
okay thanks!
we have a=-2 and r=-4 so our formula is: \[a_n=(-2) \cdot (-4)^{n-1} \]
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