Question

How do I find x in this problem? I am thinking it is going to require a change of base?
3^x=(1/3)^(x+1)

Answer 1

Recall that \(\dfrac{1}{3}=3^{-1}\), so
\[3^x=\frac{1}{3^{x+1}}~~\iff~~3^x=3^{-(x+1)}\]

Answer 2

awsome thanks!

Answer 3

yw

Answer 4

I was thinking it was along those lines.