Question

what is the simplest form of the expression ?

Answer 1

@mathmath333 help?

Answer 2

@xapproachesinfinity help please ?

Answer 3

you need rationalize the denominator
by multiplying both top and bottom by \(\huge \sqrt{3}+\sqrt{9}\) the conjugate

Answer 4

that's all i have to do ?

Answer 5

\(\large \begin{align} \color{black}{\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+ \sqrt6} \hspace{.33em}\\~\\
=\dfrac{\sqrt 3-\sqrt 6}{\sqrt 3+ \sqrt6}\times \dfrac{\sqrt 3-\sqrt 6}{\sqrt 3- \sqrt6} \hspace{.33em}\\~\\
}\end{align}\)

simplify this

Answer 6

i mean \(\huge \sqrt{3}+\sqrt{6}\)

Answer 7

ok

Answer 8

i'm drunk @mathmath333 has it the right
i did the opposite lol

Answer 9

not focused now!!

Answer 10

lol okay thanks for the help

Answer 11

it keep saying invalid input on my calculator

Answer 12

oh no if you dont have advanced calc you can do it with simple calc'
you need to do it by hand my friend otherwise what;s the point of this

Answer 13

,its -3-2 sqrt18/9 ?

Answer 14

what is \(\huge (\sqrt{3}+\sqrt{6})(\sqrt{3}-\sqrt{6})=?\)
recall \(\huge (a+b)(a-b)=a^2-b^2\) difference of two squares

Answer 15

for the top you neeed to do some foiling

Answer 16

foiling ???

Answer 17

oh nevermind i got it hold on

Answer 18

like what you do with \((a+b)(a+b)=a.a+ab+ba+b.b=a^2+2ab+b^2\)

Answer 19

sqrt 3-sqrt6/sqrt3+sqrt6=(sqrt 3-sqrt 6)(sqrt 3-6)/(sqrt3+sqrt6)(sqrt3-sqrt6)
(sqrt3-sqrt6)^2/3-6=(3-2sqrt18+6)/-3
=(9-2*3sqrt 2)/3
=(9-6sqrt2)/-3 (reduce)
=-3+2sqrt2=2sqrt2-3 < answer should be answer c then

Answer 20

yes that's good

Answer 21

good job there
sorry i had to go check my cooking hehe

Answer 22

kay