For what two values of x is the sum of these rational expressions undefined? Type your answer as two integers separated by a comma, like this: -13, 4 x + 3x2– 2x – 15+3x + 12x + 6
\[\frac{ x+3 }{ x^2-2x-15 }+\frac{ 3x+1 }{ 2x+6 }\]
@bohotness
HI!! are you supposed to add these?
o.o
yes but you factor them, and I am confused on it.
the first denominator factors as \((x-5)(x+3)\) the second one as \(2(x+3)\) making the common denominator \[2(x+3)(x-5)\]
okay i think i might be able to help
okay, so now i would just add the numerators correct?
so \[\frac{ x+3 }{ x^2-2x-15 }+\frac{ 3x+1 }{ 2x+6 }\] \[=\frac{(x+3)}{(x-5)(x+3)}\times \frac{2}{2}+\frac{3x+1}{2(x+3)}\times \frac{x-5}{x-5}\]
im not getting it
when you add fractions you do not just add up the numerators
if you added \(\frac{5}{12}+\frac{7}{18}\) what would you do?
find what would make the same denominator
yes ok lets agree that that is 36 then what?
I just dont get the numerator part of what you put up there.
the numerators would then be 15 and 14
right you had to multiply by the missing factor when you put both of those over the LCD
you have to do exactly the same thing with the variables
so the top is \[3x^2+2x-2\]
idk i didn't do it you gotta add that up, multiply out and combine like terms
Join our real-time social learning platform and learn together with your friends!