A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution?
A)0.300 M
B)0.375 M
C)6.00 M
D)7.50 M

Question

A chemistry teacher adds 50.0 mL of 1.50 M H2SO4 solution to 200 mL of water. What is the concentration of the final solution?
A)0.300 M
B)0.375 M
C)6.00 M
D)7.50 M

anonymous · Answer

dedi
what do u think

anonymous · Answer

i geuss d u

mayankdevnani · Answer

use this concept :-
$$\large \bf M_iV_i=M_fV_f$$

mayankdevnani · Answer

where,
$$\large \bf M_i=1.5 M~;V_i=50~mL~;M_f=?;V_f=50+200=250~mL$$

mayankdevnani · Answer

plug into equation and solve for Mf

mayankdevnani · Answer

hope you understand. @Dedi

anonymous · Answer

we do $$C _{1} * V _{1}  =  C _{2} *  V _{2}$$   
thene  $$C _{2}  =   \frac{ C _{1} * V _{1} }{ V _{2} }$$
so $$C _{2} = $$  50*1.5 / 200+50
$$C _{2} = $$ 0.3 M