Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

True or false?

OpenStudy (anonymous):

@freckles

OpenStudy (anonymous):

srry can't

OpenStudy (anonymous):

thats ok

OpenStudy (anonymous):

@Icedragon50

OpenStudy (anonymous):

:)

jimthompson5910 (jim_thompson5910):

that matrix they give you means that z = 5 and y = 2 use those values to find x

OpenStudy (anonymous):

7? @jim_thompson5910

OpenStudy (anonymous):

i mean -2 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

in case you're not sure how I got the values for y and z

jimthompson5910 (jim_thompson5910):

incorrect on both

jimthompson5910 (jim_thompson5910):

x - 2y + z = -2 x - 2(2) + 5 = -2 x - 4 + 5 = -2 x + 1 = -2 x = ??

OpenStudy (anonymous):

oh, -3?

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

x = -3 y = 2 z = 5

jimthompson5910 (jim_thompson5910):

that is the possible solution; however, you need to check it in each equation to make sure it's a true solution

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

the method is correct but the values am not sure of them for both 2 and 3 row

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

it is False it should be 1 -2 1 -2 0 1 0 6 0 0 1 3

OpenStudy (anonymous):

this is the elimination method multiply 1 row by a number so you can eliminate x in the 2 row and the same for thr 3 row

OpenStudy (anonymous):

(7,6,3)

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

x-2y+z = -2 7-2(6)+3 = -2 ... plug in (x,y,z) = (7,6,3) 7-12+3 = -2 -2 = -2 ... equation is true

jimthompson5910 (jim_thompson5910):

I checked the first equation and I'll let you check the other equations

jimthompson5910 (jim_thompson5910):

all 3 equations must be true when you plug in the possible solution of (x,y,z) = (7,6,3)

OpenStudy (anonymous):

i checked them and there right

jimthompson5910 (jim_thompson5910):

yes all three are true when (x,y,z) = (7,6,3)

OpenStudy (anonymous):

so this problem is true then?

OpenStudy (anonymous):

if i got all of them right?

jimthompson5910 (jim_thompson5910):

no, as AJ01 said above, it's false because of that matrix change

jimthompson5910 (jim_thompson5910):

the original matrix given to you leads to a false solution (so it can't be the proper matrix)

OpenStudy (anonymous):

ohhhh ok i see

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!