Question

show that:

Answer 1

\[\log_mn=\frac{ 1 }{ \log_nm }\]

Answer 2

@ganeshie8 @dan815 @iambatman

Answer 3

You want help proving this identity? Do you know the change of base rule?

Answer 4

so log base a of b is log b divided by log a

Answer 5

ok then what

Answer 6

Can you decompose those two into the change of base?

Answer 7

let me try

Answer 8

okie

Answer 9

@Miracrown so its
\[\log_mn=\log n/\log m\]

Answer 10

right

Answer 11

how does that become the right side

Answer 12

so now take a look at the other side... 1 / log n of m

Answer 13

a/b = 1 / (b/a), right?

Answer 14

reciprical of the reciprical.
Now, 1/(log m / log n), apply the change of base formula - what is log m divided by log n