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Solve (z+i)^4=z^4
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i is the imaginary unit, z belongs to the complex number system
I haven't seen an example quite like this in class and cannot figure it out myself. I have tried expanding and using z=a+bi and didn't get anywhere.
It's is basically a cubic in z. \((z+i)^4-z^4=0\) On expansion and simplification, \((z+i)^4-z^4=4iz^3-6z^2+4iz+1=0\)
I might have misled you. I am able to find the roots using the above expansion. But when I come to think of it, I did not have the reflex of thinking about de Moivre's theorem. Perhaps it is more intuitive looking at the given form of the problem.
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