Question

how does one simplify (solve for x) \[0\ge\frac{x^{2}-2x+3-4}{x^{2}-2x-3}\]

Answer 1

ok so
first you need to combine your like numbers so 3-4 and also x^2-2x

Answer 2

I know 3-4 = -1, what's this about x^2-2x?

Answer 3

basically what doodler said but even i dont understand that so as i was saying

Answer 4

I got this:\[0\ge\frac{x^{2}-2x-1}{x^{2}-2x-3}\]

Answer 5

And then this:\[0\ge\frac{x^{2}-2x-1}{(x-3)(x-1)}\]

Answer 6

we cant square a letter so if we ignore the "^2" what do we have

Answer 7

Top is unfactorable as far as I know

Answer 8

try this lol

Answer 9

"We can't square a letter"
...what?

Answer 10

you have X^2 or commonly know as "X squared"

Answer 11

\[\text{Aren't we solving for }x\text{ here?}\]

Answer 12

That doesn't give me x^2-2x-1...?

Answer 13

yes
but we cant solve for X untill we can combine all of our like numbers

Answer 14

They want to simplify it

Answer 15

I did combine all the like values @IMANINJA127

Answer 16

not your X values

Answer 17

Well I meant solve for x

Answer 18

And either way I'm doing the same thing aren't I?

Answer 19

well you need to combine all of your X values first before you can solve

Answer 20

I did...

Answer 21

I got \[(x-2)(x-1)= x^{2}-2x-x+2=x^{2}-3x+2\]

Answer 22

...I got lost

Answer 23

alyways if u comebine all of your like numbers
divide by the number of x etc 2x, 3x, 4x untill it is 1X= (unkown)

Answer 24

What?

Answer 25

Combined form:\[0\ge\frac{x^{2}-2x-1}{x^{2}-2x-3}\]

Answer 26

...Maybe I should just quadratic function this

Answer 27

@Abhisar

Answer 28

o-o

Answer 29

calling in the big guns here

Answer 30

I think I'll stick to @MDoodler 's explanation

Answer 31

ok

Answer 32

So is it \[(x-2)(x+1)?\]

Answer 33

nevermind

Answer 34

this might help http://www.webmath.com/redfract.html

Answer 35

how do I put this huge equation into that tiny thing though

Answer 36

@Demonx341 it's not fitting in

Answer 37

:(

Answer 38

idk xD maby put it into parts.

Answer 39

\[\text{*does not compute*}\]

Answer 40

@MDoodler I got the answer you showed me using the quadratic formula, thanks :)