Question

WILL MEDAL AND FAN!!!!!!!!!!!!!! LAST QUESTION OF MY HW!!!!!!!! Prove that a line that divides two sides of a triangle proportionally is parallel to the third side. Be sure to create and name the appropriate geometric figures.

Answer 1

xD this is hard.

Answer 2

Is this a part of your exams?

Answer 3

. . .

Why did you tell me to come here @Joel_the_boss

Answer 4

Oops, I thought you were @Joel_the_boss

@King.Void.

Answer 5

I dont know how to start this problem

Answer 6

I'm sorry but we cannot help on anything that goes on a Grade.

Answer 7

This is not for a grade. But I would like help understanding the question and learning how to find the answer.

Answer 8

Does this question belong to a test ? @livelovechloeee

Answer 9

No. I have typed it from a study guide take home practice packet.

Answer 10

something like this?

Answer 11

what grade is this?

Answer 12

Im in 10th grade, this is geometry.

Answer 13

xD i have not did geometry yet sorry.

Answer 14

See if my drawing helps you, keep trying, and see what exactly the question is asking.

Answer 15

I understand that a line is dividing the triangle in two. but what is the third side the question is referring to?

Answer 16

is this correct?

Answer 17

Given: In triangle ABC, D and E are two points, so respectively AD/DB = AE/EC.

Prove: DE is parallel to BC.

In triangle ABC, given, AD/DB = AE/EC. Let us assume that in triangle ABC, the point F is an intersect on the side AC. So we can see that AD/DB = AF/FC.

Simplify, AE/EC = AF/FC

Add 1 on both sides, (AE/EC) + 1 = (AF/FC) + 1

(AE+EC)/EC = (AF+FC)/FC

AC/EC = AC/FC

EC = FC

From the work above, we can say that the points E and F coincide on AC, and DF coincides with DE. Since DF is parallel to BC, DE is also parallel BC.

Answer 18

l